The equation of straight line which passes through the point (a cos^3 ⁡ ,a sin^3 ⁡ ) and perpendicular to x sec ⁡ +y cosec ⁡ =a is

Question

Accepted Answer

Correct answer: B. (b) : Equation of line perpendicular to x sec ⁡ +y cosec ⁡ =a is x cosec ⁡ -y sec ⁡ =k (i) (i) passes through ( a cos^3 ⁡ ,a sin^3 ⁡ ). ∴ a cos^3 ⁡ sin ⁡ - a sin^3 ⁡ cos ⁡ =k So, equation of the line is x sin ⁡ - y cos ⁡ = a cos^3 ⁡ sin ⁡ - a sin^3 ⁡ cos ⁡ ⇒ x cos ⁡ -y sin ⁡ sin ⁡ cos ⁡ = a ( cos ⁡2 ) 1 sin ⁡ cos ⁡ ⇒x cos ⁡ -y sin ⁡ =a cos ⁡2

$The equation of straight line which passes through the point (a cos^{3} θ, a sin^{3} θ) and perpendicular to x sec θ + y cosec θ = a is$

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