In a △ ABC, with usual notation, if a=12 ,b=16 and c=20, then the ratio of the exradii of the triangle opposite to the angles in the order ∠C , ∠B and ∠A is

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Correct answer: B. (b) Givena=12 ,b=16 ,c=20s= a+b+c2= 12+16+202=24 = 24 (24-12 ) (24-16 ) (24-20 ) = 24 12 8 4=96r_1= s-a= 9624-12= 9612=8r_2= s-b= 9624-16= 968=12r_3= 9624-20= 964=24 Let r_1 :r_2 :r_3=8 :12 :24 But ratio of external radii of the triangle opposite to the angles in the order ∠C , ∠B , ∠A is =24 :12 :8. =6 :3 :2

$In a △ ABC, with usual notation, if a = 12, b = 16 and c = 20, then the ratio of the exradii of the triangle opposite to the angles in the order ∠ C, ∠ B and ∠ A is$

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