- A0
- B1
- C23
- D2
Solution
(a) Given, cos25∘−cos215∘−sin215∘+sin235∘
+cos15∘sin15∘−cos5∘sin35∘
After rearranging the terms
=cos5∘(cos5∘−sin35∘)−cos15∘((cos15∘−sin15∘)+sin235∘−sin215∘
=cos5∘(cos5∘−cos55∘)−cos15∘(cos15∘−cos75∘)+sin50∘sin20∘
=−2cos15∘+cos5∘sin25∘+sin50∘sin20∘
=−2cos15∘+21(cos70∘+cos60∘+cos30∘−cos70∘)
=−2cos15∘+21(2cos45∘cos15∘)
=−2cos15∘+2cos15∘=0
Hence, option (a) is correct.More Trigonometric Ratios & Identities PYQs
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