An electric field, E= 2i+6j+8k 6 passes through the surface of 4 m^2 area having unit vector n= ( 2i+j+k 6 ). The electric flux for that surface is_____ Vm.

Question

Accepted Answer

Correct answer: 12. (12) =E A = ( 2i+6j+8k 6 ) 4 ( 2i+j+k 6 ) = 46 (4+6+8 )=12Vm

$An electric field, E = \frac{2 i + 6 j + 8 k}{6} passes through the surface of 4 m^{2} area having unit vector n = (\frac{2 i + j + k}{6}) . The electric flux for that surface is_____ Vm.$

Solution

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