An inclined plane is bent in such a way that the vertical cross-section is given by y= x^24 where y is in verticaland x in horizontal direction. If the upper surface of this curved plane is rough wit…

Question

An inclined plane is bent in such a way that the vertical cross-section is given by y= x^24 where y is in verticaland x in horizontal direction. If the upper surface of this curved plane is rough with coefficient of friction =0.5, the maximum height in cm at which a stationary block will not slip downward is___.

Accepted Answer

Correct answer: 25. (25) given y= x^24 =0.5 condition for block will not slip downward mgsin ⁡ = μmgcos ⁡ ⇒ tan ⁡ = and we Know that ⇒ tan ⁡ = dy dx ⇒ dy dx= ⇒ x2=0.5 ( \&y= x^24 \& dy dx= x2) ⇒x=1 put x=1in equation y=x^2/4 ⇒y= (1 )^24 ⇒y= 14 ⇒y=0.25 y=25 cm

Solution

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