JEE Previous Year Question

A composite block is made of slabs A, B, C, D and E of different thermal conductivities (given in terms of a constant K) and sizes (given in terms of length, L) as shown in the figure. All slabs are of same width. Heat ‘Q’ flows only from left to right through the blocks. Then in steady state

Topic: JEE PYQ

Answer: A, C, D. Full step-by-step solution below.

  1. Aheat flow through A and E slabs are same
  2. Bheat flow through slab E is maximum
  3. Ctemperature difference across slab E is smallest
  4. Dheat flow through C = heat flow through B + heat flow through D.

Correct answer: A, C, D

Solution

(a, c, d)
(a): At steady state, heat flow through A and E are same.
(c): T = i × R
‘i’ is same for A and E but R is smallest for E.
(d): iB =
=
iD =
if = iB + iD
Hence

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