A radioactive substance decays to ( 116 )^ th of its initial activity in 80 days. The half life of the radioactive substance expressed in days is ____.

Question

Accepted Answer

Correct answer: 20. (20) N_0 t_1/2 N_02 t_1/2 N_04 t_1/2 N_08 t_1/2 N_016 4 × t_1/2 = 80 t_1/2 = 20 days

$A radioactive substance decays to (\frac{1}{16})^{th} of its initial activity in 80 days. The half life of the radioactive substance expressed in days is ____.$

Solution

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