A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain i…

Question

A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the binding energy in the process is [NEET 2021]

Accepted Answer

Correct answer: D. (d) A nucleus with mass number 240 breaks into two fragments each of mass number 120. X^240 ⟶Y^120+Z^120 Given, the binding energy per nucleon of unfragmented nuclei, X=7.6 MeV The binding energy per nucleon of fragmented nuclei, Y=Z=8.5 MeV Now, we shall determine the total gain in binding energy. Gain in binding energy = Binding energy of products Binding energy of reactants Gain in binding energy =2 120 8.5-240 7.6 =216 MeV

$A nucleus with mass number 240 breaks into two fragments each of mass number 120, the binding energy per nucleon of unfragmented nuclei is 7.6 MeV while that of fragments is 8.5 MeV. The total gain in the binding energy in the process is [NEET 2021]$

Solution

More Nuclei PYQs