A solid sphere of radius 10 cm is rotating about an axis which is at a distance 15 cm from its centre. The radius of gyration about this axis is n cm. The value of n is

Question

Accepted Answer

Correct answer: 265. (265) Using the parallel axis theorem for radius of gyration: k^2=k_ cm^2+d^2 where k_ cm is the radius of gyration about the center of mass and d is the distance from the center. For a solid sphere: I_ center= 25MR^2, so k_ cm^2= 25R^2 With R=10 cm and d=15 cm : k^2= 25 (10 )^2+ (15 )^2=40+225=265Since k= n, we have n=265.

$A solid sphere of radius 10 cm is rotating about an axis which is at a distance 15 cm from its centre. The radius of gyration about this axis is n cm . The value of n is$

Solution

More Rotational Mechanics PYQs