JEE Previous Year Question

A physical quantity $Q$ is related to four observables $a\text{,}b\text{,}c\text{,}d$ as follows : $Q=\frac{{\text{ab}}^4}{\text{cd}}$ where, $a$
$\text{(}60\pm 3\text{)}\text{Pa}\text{;}b=\text{(}20\pm 0.1\text{)}m\text{;}c=\text{(}40\pm 0.2\text{)}{\text{Nsm}}^{-2}$ and $d=\text{(}50\pm 0.1\text{)}m$, then the percentage error in Q is $\frac{x}{1000}$, where $x=$ .

Topic: JEE PYQ

Answer: 7700. Full step-by-step solution below.