In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division.Then the value of vernier constant will be.…

Question

In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division.Then the value of vernier constant will be.............. x 10^-2 mm

Accepted Answer

Correct answer: 5. (5) 20 MSD = 1 cm 1MSD = 120cm 10VSD = 9MSD 1VSD = 910MSD = 910 120 cm = 910 120 cm 1 VSD= 9200 cm VC = 1 MSD - 1 VSD = 120 cm- 9200 cm = 1200 10 mm VC=5 10^-2 mm Ans. 5

$In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division.Then the value of vernier constant will be.............. x 1 0^{- 2} mm$

Solution

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