Molecular AB has a bond length of 1.61 A and a dipole moment of 0.38 D. The fractional charge on each atom (absolute magnitude) is: (e_0 = 4.802 × 10^–10esu)

Question

Accepted Answer

Correct answer: B. (b) 0.38= 1.617 10^-810^-18 =0.235 10^-10 Fraction= 0.235 10^-104.8 10^-10=0.05

$Molecular AB has a bond length of 1.61 A and a dipole moment of 0.38 D. The fractional charge on each atom (absolute magnitude) is: ( = 4.802 × esu)$

Solution

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