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JEE · NEET Previous Year Question

Which statements are NOT TRUE about XeO2 F2 ?(A) It has a see-saw shape.(B) Xe has 5 electron pairs in its valence shell in XeO2 F2.(C) The bond angle is close to 180∘.(D) The bond angle is close to 180∘.(E) Xe has 16 valence electrons in XeO2 F2.
Choose the correct answer from the options given below:

Topic: JEE PYQ

Answer: A. Full step-by-step solution below.

  1. A(B) (C) and (E) Only
  2. B(B) and (D) Only
  3. C(A) and (D) Only
  4. D(B) (D) and (E) Only

Correct answer: A

Solution

(a) In : Xe has 8 valence electrons forming 4 bonding pairs ( 2 with with F ) and 2 lone pairs, giving a trigonal bipyramidal electron geometry with a see-saw molecular shape, making statement A TRUE.
Statement B is NOT TRUE because the total electron pairs around Xe is 6 ( 4 bonding +2 lone), not 5 .
For statement C, the O-Xe-O angle in a see-saw geometry is approximately , not close to , making it not true.
Statement D is TRUE as the F-Xe-F angle is approximately when F atoms occupy axial positions.
Statement E is NOT TRUE since Xe has only 8 valence electrons, not 16 .
The incorrect statements are B, C, and E.

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