Consider the reaction X_2Y (g )=X_2 (g )+ 12Y_2 (g ) The equation representing correct relationship between the degree of dissociation (x) of X_2Y (g ) with its equilibrium constant Kp is . Assume x…

Question

Consider the reaction X_2Y (g )=X_2 (g )+ 12Y_2 (g ) The equation representing correct relationship between the degree of dissociation (x) of X_2Y (g ) with its equilibrium constant Kp is . Assume x to be very very small.

Accepted Answer

Correct answer: B. (c) 1 mol X_2Y (g ) XxX_2 (g )+ 12Y_2 (g ) x2 ∴P_x_2y = 1-x1+ x2 p P_x_2= x1+ x2 p P_y_2= x/21+ x2 p ∴K_p= ( x1+ x2p ) ( x2(1+ x2)p )^1/2 ( 1-x1+ x2 ) p ∴K_p= ( x1-x ) ( x2(1+ x2) )^1/2 p^1/2 ∴x to be very small ∴K_p= x^3/22^ (1/2 ) p^1/2 ∴x^3/2= K_p 2^1/2p^1/2x^3= K_p^2 2px= ( K_p^2 2p )^1/3

$Consider the reaction X_{2} Y (g) = X_{2} (g) + \frac{1}{2} Y_{2} (g) The equation representing correct relationship between the degree of dissociation (x) of X_{2} Y (g) with its equilibrium constant Kp is . Assume x to be very very small.$

Solution

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