The equilibrium constant for the reaction, $N_{2 (g)} + O_{2 (g)} ⇌ 2 NO_{(g)}$ is $4 \times 10^{- 4}$ at $2000 K$ . In presence of a catalyst, the equilibrium is attained ten times faster. Therefore, the
equilibrium constant in presence of catalyst at $2000 K$ is

Question

The equilibrium constant for the reaction,

N_{2 (g)} + O_{2 (g)} ⇌ 2 NO_{(g)}

is

4 \times 10^{- 4}

at

2000 K

. In presence of a catalyst, the equilibrium is attained ten times faster. Therefore, the
equilibrium constant in presence of catalyst at

2000 K

is

Accepted Answer

Correct answer: C. (c) : Equilibrium constant is independent of the presence of catalyst. This is so because the catalyst affects the rates of forward and backward reactions equally.

$The equilibrium constant for the reaction, N_{2 (g)} + O_{2 (g)} ⇌ 2 NO_{(g)} is 4 \times 10^{- 4} at 2000 K . In presence of a catalyst, the equilibrium is attained ten times faster. Therefore, the equilibrium constant in presence of catalyst at 2000 K is$

Solution

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