For the following reactions, equilibrium constants are given:
$S (s) + O_{2} (g) ⇌ SO_{2} (g); K_{1} = 10^{52}$
$2 S (s) + 3 O_{2} (g) ⇌ 2 SO_{3} (g); K_{2} = 10^{129}$
The equilibrium constant for the reaction, $2 SO_{2} (g) + O_{2} (g) ⇌ 2 SO_{3} (g)$ is:

Question

For the following reactions, equilibrium constants are given:

S (s) + O_{2} (g) ⇌ SO_{2} (g); K_{1} = 10^{52}

2 S (s) + 3 O_{2} (g) ⇌ 2 SO_{3} (g); K_{2} = 10^{129}

The equilibrium constant for the reaction,

2 SO_{2} (g) + O_{2} (g) ⇌ 2 SO_{3} (g)

is:

Accepted Answer

Correct answer: C. (c) Given, S+O_2 ⇌ SO_2 … (i ) ;K_1=10^52 2S+3O_2 ⇌2 SO_3 … ( ii ) ;K_2=10^129 2 SO_2+O_2 ⇌2 SO_3 … ( iii ) ;K= ? To get equation ( iii ) follow ( ii )-2 (i ) , 2S+3O_2 2 SO_3K=10^129 -(2S+2O_2 2 SO_2k=10^104) O_2 2 SO_3-2 SO_2K=10^25 or 2 SO_2+O_2 2 SO_3K=10^25

$For the following reactions, equilibrium constants are given: S (s) + O_{2} (g) ⇌ SO_{2} (g); K_{1} = 10^{52} 2 S (s) + 3 O_{2} (g) ⇌ 2 SO_{3} (g); K_{2} = 10^{129} The equilibrium constant for the reaction, 2 SO_{2} (g) + O_{2} (g) ⇌ 2 SO_{3} (g) is:$

Solution

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