30 cc of M3 HCl ,20 cc of M2 HNO_3 and 40 cc of M4 NaOH solutions are mixed and the volume was made up to 1 dm^3. The pH of the resulting solution is

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Correct answer: A. (a) : Total milliequivalents of H^+ =20 12+30 13=20 Total milliequivalents of OH^-=40 14=10 Thus, milliequivalents of H^+left =20-10=10 Total volume of solution =1 dm^3=1000 mL ∴ (H^+ )= 101000=10^-2 ⇒ pH=- log ⁡ (H^+ )=- log ⁡ (10^-2 )=2

$30 cc of \frac{M}{3} HCl, 20 cc of \frac{M}{2} HNO_{3} and 40 cc of \frac{M}{4} NaOH solutions are mixed and the volume was made up to 1 dm^{3} . The pH of the resulting solution is$

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