MereTeacher

JEE • NEET • FOUNDATION

JEE · NEET Previous Year Question

$Calculate half life of first order reaction if rate constant of reaction is 2.772 \times 10^{- 3} s^{- 1} .$

Topic: JEE PYQ

Answer: B. Full step-by-step solution below.

A $125 s$
B $250 s$
C $100 s$
D $150 s$

Correct answer: B

Solution

(b): Given, k = 2.772 \times 10^{- 3} s^{- 1} For a first order reaction, t_{1/2} = \frac{0.693}{k} = \frac{0.693}{2.772 \times 10 ^{- 3}} = 0.25 \times 10^{3} = 250 s

More Chemical Kinetics PYQs

$A \to product (First order reaction). Three sets of experiment were performed for a reaction under similar experimental conditions:\dots$
$The rate constant of a reaction increases by five times on increase in temperature from 27°C to 52°C. Thevalue of activation energ\dots$
$If 75 % of a first order reaction was completed in 90 minutes, 60 % of the same reaction would be completed in\dots$
$The reaction 2 A \to 2 B + C has a rate constant of 1.2 \times 10^{- 2} s^{- 1} . Which of the following is correct?$
$2 A \to B + C It would be a zero order reaction when$