Two electrolytic cells are connected in series containing CuSO_4 solution and molten AlCl_3. If in electrolysis 0.4 moles of 'Cu' are deposited on cathode of first cell, the number of moles of 'Al' d…

Question

Two electrolytic cells are connected in series containing CuSO_4 solution and molten AlCl_3. If in electrolysis 0.4 moles of 'Cu' are deposited on cathode of first cell, the number of moles of 'Al' deposited on cathode of the second cell is

Accepted Answer

Correct answer: B. (b) : Cu^2++2e^- ⟶ Cu Thus for 1 mole of Cu, charge required =2 F For 0.4 mole of Cu, charge required = (2/1 ) 0.4=0.8 F For Al , Al^3++3e^- ⟶ Al For 1 mole of Al, charge required =3 F Thus from 0.8 F, Al will deposit = (1/3 ) 0.8=0.27 mole

$Two electrolytic cells are connected in series containing CuSO_{4} solution and molten AlCl_{3} . If in electrolysis 0.4 moles of 'Cu' are deposited on cathode of first cell, the number of moles of 'Al' deposited on cathode of the second cell is$

Solution

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