Standard electrode potentials are F e^2+/F e; E^o=−0.4 4 and F e^3+/F e^2+;E^o=0.7 7 F e^2+,F e^3+and Fe blocks are kept together, then

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Correct answer: B. (b) The metals having higher negative values of their electrode potential can displace metals having lower values from their salt solutions.

$Standard electrode potentials are F e^{2 +} / F e; E^{o} = - 0.44 and F e^{3 +} / F e^{2 +}; E^{o} = 0.77 F e^{2 +}, F e^{3 +} and Fe blocks are kept together, then$

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