The correct order of reactivity of CH_3 Br in methanol with the following nucleophiles is F^- ,I^- ,C_2H_5O^-and C_6H_5O^-

Question

Accepted Answer

Correct answer: B. (b) In methanol (protic solvent), nucleophilicity is determined by basicity and solvation effects. Smaller ions are heavily solvated by the protic solvent, reducing their effective nucleophilicity. C_2H_5O^-(ethoxide) is the strongest nucleophile as it is less solvated and highly basic. C_6H_5O^-(phenoxide) is weaker due to resonance stabilization by the benzene ring. F^-is highly solvated despite high basicity, reducing its nucleophilicity significantly. I^-is the best nucleophile because it is the largest ion and least solvated in methanol. The correct order is I^->C_2H_5O^->C_6H_5O^->F^-.

$The correct order of reactivity of CH_{3} Br in methanol with the following nucleophiles is F^{-}, I^{-}, C_{2} H_{5} O^{-} and C_{6} H_{5} O^{-}$

Solution

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