Given below are two statements:
Statement I: One mole of propyne reacts with excess of sodium to liberate half a mole of $H_{2}$ gas
Statement II: Four g of propyne reacts with $NaNH_{2}$ to liberate $NH_{3}$ gas which occupies 224 mL at STP.
choose the most appropriate answer from the options given below:

Question

Given below are two statements:
Statement I: One mole of propyne reacts with excess of sodium to liberate half a mole of

H_{2}

gas
Statement II: Four g of propyne reacts with

NaNH_{2}

to liberate

NH_{3}

gas which occupies 224 mL at STP.
choose the most appropriate answer from the options given below:

Accepted Answer

Correct answer: C. (c) CH_3-C ≡ CH+ Na CH_3-C ≡C^- Na^++ 12H_2 Statement-1 is correct. Moles of C_3H_4= 440=0.1 mole CH_3-C ≡ CH+ NaNH_2 CH_3-C ≡C^- Na^++ _ NH_30.1 mole 0.1 mole Volume of NH_3= (0.1 ) (22.4 )=2.24 L Statement-II is incorrect.

Solution

More Hydrocarbons PYQs