200 m L of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.5 7×1 0^−3 bar. The molar mass of protein will be(R=0.0 8 3 L bar m o…

Question

200 m L of an aqueous solution of a protein contains its 1.26 g. The osmotic pressure of this solution at 300 K is found to be 2.5 7×1 0^−3 bar. The molar mass of protein will be(R=0.0 8 3 L bar m o l^−1K^−1)

Accepted Answer

Correct answer: D. (d) We know that π V=n R T, where n= wM π V= wMR T M= w R Tπ V= 1 2 6×0 0 8 3×3 0 02.5 7×1 0^−3× 2 0 01 0 0 0= 1 2 6×0.0 8 3×3 0 02.5 7×1 0^−3×0 2 =6 1 0 3 8 g m o 1^−1

$200 m L of an aqueous solution of a protein contains its 1.26 g . The osmotic pressure of this solution at 300 K is found to be 2.57 \times 1 0^{- 3} bar. The molar mass of protein will be (R = 0.083 L bar m o l^{- 1} K^{- 1})$

Solution

More Solutions PYQs