8 g of NaOH is dissolved in 18 g of H_2O. Mole fraction of NaOH in solution and molality (in mol Kg^-1) of the solution respectively are :

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Correct answer: C. (c) No. of moles of H_2O (n_1 )= 1818=1 No. of moles of NaOH (n_2 )= 840= 15 Mole fraction of NaOH = n_2n_2+n_1= 15 15+1=0.167 Molality = No . of moles of solute Mass of solvent ( kg ) = 15 100018=11.11m

$8 g of NaOH is dissolved in 18 g of . Mole fraction of NaOH in solution and molality (in mol) of the solution respectively are :$

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