When 20 g of naphthoic acid (C_11H_8O_2) is dissolved in 50 g of benzene (K_f = 1.72 K kg mol^–1), a freezing point depression of 2 K is observed. The van’t Hoff factor (i) is:

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Correct answer: A. (a) ∆ T_f = i × K_f × molality Þ 2 = i × 1.72 × 2 01 7 2× 1 0 0 05 0 Þ 2 = 4i Þ i = 1/2 = 0.5

$When 20 g of naphthoic acid (C_{11} H_{8} O_{2}) is dissolved in 50 g of benzene (K_{f} = 1.72 K kg m o l^{-1}), a freezing point depression of 2 K is observed. The van’t Hoff factor (i) is:$

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