15 \% aqueous solution of glucose (molecular weight =180 g/ mol ) is isotonic with 8 \% aqueous solution containing an unknown non-dissociable solute. What is the molecular weight of the unknown solu…

Question

15 \% aqueous solution of glucose (molecular weight =180 g/ mol ) is isotonic with 8 \% aqueous solution containing an unknown non-dissociable solute. What is the molecular weight of the unknown solute?

Accepted Answer

Correct answer: B. (b) _1 ( glucose )= _2 ( unknown solute ) ⇒C_1 ( glucose )=C_2 ( unknown solute ) ⇒ ( w_B 1000m_B V )_ Glucose= ( w_B 1000m_B V )_ Unknown solute ⇒ ( 15 1000180 100 )= ( 8 1000m_B 100 ) ⇒m_B= 180 100 8 100015 1000 100 ⇒m_B=96

$15 % aqueous solution of glucose (molecular weight = 180 g / mol) is isotonic with 8 % aqueous solution containing an unknown non-dissociable solute. What is the molecular weight of the unknown solute?$

Solution

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