The most probable velocity of a gas at 7200 K is equal to the RMS velocity of He gas at 27^ C. The gas is

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Correct answer: D. (d) Given, most probable velocity at 7200 K = RMS velocity of He gas at 300 K 2 RT_1M_1= 3 RT_2M_2 ⇒ 2 RT_1M_1= 3 RT_24( ∴ Atomic mass of He=4 amu ) 2 R 7200M_1= 3 R 3004 ⇒ 2 7200M_1= 9004 M_1= 2 7200 4900=64 (Mass of SO_2 )

$The most probable velocity of a gas at 7200 K is equal to the RMS velocity of He gas at 27^{\circ} C . The gas is$

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