What is the total pressure exerted by the mixture of 7.0 g of N_2, 2 g of hydrogen and 8.0 g of sulphur dioxide gases in a vessel of 6 L capacity that has been kept in a reservoir at 27°C?

Question

Accepted Answer

Correct answer: D. (d)No. of moles of N_2 = 72 8 = 14 No. of moles of H_2 = 1 Mole Total moles = 14 + 1 + 18 No. of moles of SO_2 = 18moles = 18(2 + 8 + 1) = 1 18 P = n R TV = 1 18 × 0.0 8 2 1×3 0 06 = 5.64 ≈ 5.7 atm.

$What is the total pressure exerted by the mixture of 7.0 g of N_{2}, 2 g of hydrogen and 8.0 g of sulphur dioxide gases in a vessel of 6 L capacity that has been kept in a reservoir at 27°C?$

Solution

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