Calculate the PV type of work for the following reaction at 1 bar pressure. C_3H_6 (g ) (150 mL )+ HCl_ (g ) (150 mL ) ⟶C_3H_7 Cl_ (g ) (150 mL )

Question

Accepted Answer

Correct answer: C. (c) : V_1=150+150 mL=300 mL=0.3 L V_2=150 mL=0.15 L P=1 bar W=-P V=-1 (0.15-0.3 )=- (-0.15 )=0.15 L bar ≈15I ( 1 Lbar=101.3 J )

$Calculate the PV type of work for the following reaction at 1 bar pressure. C_{3} H_{6 (g)} (150 mL) + HCl_{(g)} (150 mL) ⟶ C_{3} H_{7} Cl_{(g)} (150 mL)$