A certain engine which operates in a carnot cycle absorbs 3.347 kJ at 400ºC, how much work is done by the engine per cycle ? The temperature of sink is 100ºC.

Question

Accepted Answer

Correct answer: A. (a) h = T_2−T_1T_2 = 1– T_1T_2 = 1– 373673 = 0.446 h = ∆wq_1 or DW = h × q_1 = 0.446 × 3.347 = 1.49 kJ

$A certain engine which operates in a carnot cycle absorbs 3.347 kJ at 400ºC, how much work is done by the engine per cycle ? The temperature of sink is 100ºC.$

Solution

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