A car is travelling at 30 ms^-1 speed on a circular road of radius 300m. If its speed is increasing at the rate of 4 ms^-2, then its acceleration is

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Correct answer: D. (d) Velocity of car, V=30m/s Radius of road, R=300m. Tangential acceleration, a_T=4m/s^2 Centripetal acceleration, a_C= V^2R ∴a_C= 30 30300=3m/s^2 Net acceleration is given as: a_T= a_T^2+a_C^2= (3 )^2+ (4 )^2=5m/s^2

$A car is travelling at 30 ms^{- 1} speed on a circular road of radius 300 m . If its speed is increasing at the rate of 4 ms^{- 2}, then its acceleration is$

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