A mosquito is moving with a velocity v=0.5t^2i+3tj+9km/s and accelerating in uniform conditions.What will be the direction of mosquito after 2s?

Question

Accepted Answer

Correct answer: B. (b) Given v=0.5t^2i+3tj+9k v_ at=2=2i+6j+9k ∴Angle made by direction of motion of mosquito will be, cos^-1 ⁡ 211 ( fromx- axis )= tan^-1 ⁡ 1172 cos^-1 ⁡ 611(from y -axis ) = tan^-1 ⁡ 856 cos^-1 ⁡ 911(from z -axis ) = tan^-1 ⁡ 409

$A mosquito is moving with a velocity v = 0.5 t^{2} i + 3 t j + 9 k m / s and accelerating in uniform conditions.What will be the direction of mosquito after 2 s ?$

Solution

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