A particle initially at origin starts moving in xy-plane has velocity component V= (6+2t )i+ (4+2 3t )j m/s. Acceleration of the particle in m/s^2 is [x, y are measured in metres, t in seconds, respe…

Question

A particle initially at origin starts moving in xy-plane has velocity component V= (6+2t )i+ (4+2 3t )j m/s. Acceleration of the particle in m/s^2 is [x, y are measured in metres, t in seconds, respectively]

Accepted Answer

Correct answer: C. (c) We have, a_x= dV_x dt= d dt (6+2t )=2a_y= dV_y dt= d dt (4+2 3t )=2 3 So, a=a_xi+a_yj=2i+2 3j

$A particle initially at origin starts moving in xy-plane has velocity component V = (6 + 2 t) i + (4 + 23 t) j m / s . Acceleration of the particle in m / s^{2} is [x, y are measured in metres, t in seconds, respectively]$

Solution

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