In a photo electric experiment, the wavelength of the light incident on the metal is changed from 200 nm to 400 nm. The decrease in the stopping potential is close to [Use hc =1240 eV-nm where h= Pla…

Question

In a photo electric experiment, the wavelength of the light incident on the metal is changed from 200 nm to 400 nm. The decrease in the stopping potential is close to [Use hc =1240 eV-nm where h= Planck's constant and c is velocity of light].

Accepted Answer

Correct answer: A. (a) eV_S= hc - hc _0 V_S= hce( 1 - 1 _0) So ,V_S1=1240( 1200- 1 _0) V_S2=1240( 1400- 1 _0) So ,V_S1-V_S2=1240( 1200- 1400) =1240 (5-2.5 ) 10^-3=3.1 V

$In a photo electric experiment, the wavelength of the light incident on the metal is changed from 200 nm to 400 nm . The decrease in the stopping potential is close to [Use hc = 1240 eV -nm where h = Planck's constant and c is velocity of light].$

Solution

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