The energy that should be added to an electron to reduce ils de-Broglie wavelength from 1 nm to 0.5 nm is

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Accepted Answer

Correct answer: D. (d) de-Broglie wavelength, = h 2 mk ⇒ ∝ 1 K .E . Given, Initial de-Broglie wavelength, _1=1 nm Final de-Broglie wavelength, _2=0.5 nm ∴ Kinetic energy (KE) ∝ 1 ^2 ∴ KE_2 KE_1= ( _1 _2 )^2 ⇒ KE_2 KE_1= ( 10.5 )^2 ⇒ KE_2=4 KE_1 Hence, the kinetic energy is increases three times. ∴ KE=3 KE_1

$The energy that should be added to an electron to reduce ils de-Broglie wavelength from 1 nm to 0.5 nm is$

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