On a photosensitive material, when frequency of incident radiation is increased by 30 \%, kinetic energy of emitted photoelectrons increases from 0.4 eV to 0.9 eV. The work function of the surface is

Question

Accepted Answer

Correct answer: B. (b) The kinetic energy of the electron is K.E. = hv- _0 hv=K .E .+ _0 hv=0.4+ _0 Given, frequency of incident radiation is increased by 30 \% ∴ lw+ 300100 lw=1.3/h 1.3/10=0.9+ _0 or 0.38=0.3 _0 ⇒ _0= 0.380.3=1.267cV

$On a photosensitive material, when frequency of incident radiation is increased by 30 %, kinetic energy of emitted photoelectrons increases from 0.4 eV to 0.9 eV . The work function of the surface is$

Solution

More Dual Nature of Matter & Radiation PYQs