Identical charges (-q) are placed at each corners of cube of side b then electrostatic potential energy of charge (+q) which is placed at centre of cube will be

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Correct answer: C. (c) There are eight corners of a cube and in each corner there is a charge of (-q). At the centre of the corner there is a charge of (+q). Each corner is equidistant from the centres of the cube and the distance (d) is half of the diagonals of the cube. Diagonal of the cube = b^2+b^2+b^2= 3b ∴d= 3b/2 Now, electric potential energy of the charge (+q) due to a charge (-q) at one corner = U = q_1q_24 _0^ = (+q) (-q)4 _0( 3b/2)=- q^22 _0 ( 3b ) Total electric potential energy due to all the eight identical charges =8U=- 8q^22 _0^ 3b= -4q^2 3 _0b

$Identical charges (-q) are placed at each corners of cube of side b then electrostatic potential energy of charge (+q) which is placed at centre of cube will be$

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