The net electric flux due to a uniform electric field of 3 10^31 NC^-1 through a cube of side 20 cm oriented such that its faces are parallel to the coordinate planes is

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Correct answer: C. (c) Uniform electric field, E=3 10^3iN/C side of cube, a=20 cm=0.20 m Four face makes the angle between area vector and electric field is 90^ . = ( EdAcos ⁡90 ) 4=0 One face makes the angle between area vector and electric field is 0^ _1=E . Acos ⁡0= EA Other face makes the angle between area vector and electric field is 180^ _2= EAcos ⁡180=- EA The net electric flux is _ net= _1+ _2 = EA- EA=0^ '

$The net electric flux due to a uniform electric field of 3 \times 10^{3} 1 NC^{- 1} through a cube of side 20 cm oriented such that its faces are parallel to the coordinate planes is$

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