A particle of mass m and charge q travelling with a velocity v along the x-axis enters a uniform electric field E directed along the y-axis. What will be the trajectory of the particle?

Question

Accepted Answer

Correct answer: C. (c) y= ut+ 12 at^2 ( ∵u=0 ) y= 12 at^2 F= ma=qE a= qEm y= 12 qEm x^2v^2 ( ∵x= vv ) x^2= 2mv^2 qEy Compair with x^2=4 ay So, the trajectory of the particle will be parabolic.

$A particle of mass m and charge q travelling with a velocity v along the x-axis enters a uniform electric field E directed along the y-axis. What will be the trajectory of the particle?$

Solution

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