A spherical volume contains a uniformly distributed charge of density $1.0 \times 10^{- 6} C / m^{3}$ . Find the electrical field (in $N / C$ ) at a point inside the volume at a distance 1 $mm$ from the centre.
$(Let (\frac{1}{4 π ϵ _{0}} = 9 \times 10^{9} Nm^{2} C^{- 2})$

Question

A spherical volume contains a uniformly distributed charge of density

1.0 \times 10^{- 6} C / m^{3}

. Find the electrical field (in

N / C

) at a point inside the volume at a distance 1

mm

from the centre.

(Let (\frac{1}{4 π ϵ _{0}} = 9 \times 10^{9} Nm^{2} C^{- 2})

Accepted Answer

Correct answer: D. (d) Charge density =1 10^-6C/m^3 Radius (R )=1 mm Charge on sphere of radius R q = charge density volume =10^-6 43 R^3 ∴ Electric field at a distance r on surface of sphere E= 14 _0 qR^2 E= 14 _0 10^-6 43 R^3R^2= 14 _0 10^-6 4 πR3 Putting the given values, we get E=9 10^9 10^-6 4 10^-53=12 πN/C

$A spherical volume contains a uniformly distributed charge of density 1.0 \times 10^{- 6} C / m^{3} . Find the electrical field (in N / C) at a point inside the volume at a distance 1 mm from the centre. (Let (\frac{1}{4 π ϵ _{0}} = 9 \times 10^{9} Nm^{2} C^{- 2})$

Solution

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