The electric potential at a place is varying as V= 12(y^2-4x) volt. Then the electric field at x=1 m and y=1 m is

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Correct answer: C. (c) Electric potential is given by V= 12(y^2-4x) E_x= dV dx=-( 12x-4)=2 V/m E_y= - dV dv= 12 2y=y=-1V/m The electric field at x=1 m and y=1 m is E=E_xi+E_yj =2i-jVm^-1

$The electric potential at a place is varying as V = \frac{1}{2} (y^{2} - 4 x) volt. Then the electric field at x = 1 m and y = 1 m is$

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