Two blocks of masses W_1 and W_2 are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up with an acceleration ' g ', then the tension in the strin…

Question

Two blocks of masses W_1 and W_2 are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up with an acceleration ' g ', then the tension in the string will be

Accepted Answer

Correct answer: A. (a) For mass W_1 W_1a-W_1a_0=W_1g-TW_1a-W_1g=W_1g-TW_1a=2W_1g-T … (i ) For mass W_2 W_2a+W_2a_o=T-W_2gW_2a+W_2g=T-W_2gW_2a=T-2W_2g … . . ( ii ) Adding equation (i) and (ii), We have W_1a+W_2a=2W_1g-2W_2ga= 2g(W_1-W_2)W_1+W_2 Put this value in equation (i) W_1 2 g( W_1-W_2)W_1+W_2=2 W_1 g-T 2 gW_1^2 W_1+W_2- 2 gW_1 W_2 W_1+W_2=2 W_1 g-TT=2 W_1 g- 2 gW_1^2 W_1+W_2+ 2 gW_1 W_2 W_1+W_2 = 2g( W_1^2+W_1 W_2-W_1^2+W_1 W_2)W_1+W_2 = 4 W_1 W_2 g W_1+W_2

$Two blocks of masses W_{1} and W_{2} are suspended from the ends of a light string passing over a smooth fixed pulley. If the pulley is pulled up with an acceleration ' g', then the tension in the string will be$

Solution

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