A black body is at a temperature of 2880K. The energy of radiation emitted by this object with wave length between 499 nm and 500 nm is U_1, between 999 nm and 1000 nm is U_2 and between 1499 nm and…

Question

A black body is at a temperature of 2880K. The energy of radiation emitted by this object with wave length between 499 nm and 500 nm is U_1, between 999 nm and 1000 nm is U_2 and between 1499 nm and 1500 nm is U_3. Wein constant b=2.88 x 10^6nmK. Then

Accepted Answer

Correct answer: D. (d) From wein’s Law _mT constant. Where T is temperature of black body and _m is wavelength corresponding to maximum energy of emission. Energy distribution of blackbody radiation is given below: (1) U_1 and U_3 are not zero because a blackbody emits nearly radiation’s of all wavelengths. (2) Since U_1 corresponds lower wavelength and U_3 corresponds higher wavelength and U_2 corresponds medium wavelength. Hence U_2 >U_1.

$A black body is at a temperature of 2880K. The energy of radiation emitted by this object with wave length between 499 nm and 500 nm is U_{1}, between 999 nm and 1000 nm is U_{2} and between 1499 nm and 1500 nm is U_{3} . Wein constant b=2.88 x 1 0^{6} nmK. Then$

Solution

More Heat Transfer PYQs