A projectile is given an initial velocity of i+2j ms^-1. The cartesian equation of its path is ( x and y are in metres and g=10 ms^-1 )

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Correct answer: B. (b) Cartesian equation path of projectile is given by y=x tan ⁡ - gx^22u^2 cos^2 ⁡ Given velocity u=i+2jm/s |u |= 1^2+2^2= 5 , tan ⁡ = 21=2 cos ⁡ = 1 5 ∴y=x 2- g^22 ( 5 )^2 ( 1 5 )^2=2x- 10 x^210 15 ∴y=2x-5x^2 .

$A projectile is given an initial velocity of i + 2 j ms^{- 1} . The cartesian equation of its path is (x and y are in metres and g = 10 ms^{- 1})$

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