The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectiles is:

Question

Accepted Answer

Correct answer: B. (b) Horizontal range R = u^2 sin2 g ......(i) maximum height H = u^2 sin2 2g .......(ii) here (a) = (b) u^2 sin2 g= u^2 sin^2 2g 2 sin θ = sin 2 θ = tan^–1 (4)

$The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectiles is:$

Solution

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