A car travels in a straight line along a road. Its distance x from a stop sign is given as a function of t by the equation x (t )= αt+ t^3, where =2.0m/s , =0.01m/s^3. Calculate the average velocity…

Question

A car travels in a straight line along a road. Its distance x from a stop sign is given as a function of t by the equation x (t )= αt+ t^3, where =2.0m/s , =0.01m/s^3. Calculate the average velocity of the car in the time interval t=2.00s to 4.00s.

Accepted Answer

Correct answer: A. (a) x=x (t_2 )-x (t_1 )x= (t_2-t_1)+ (t_2^3-t_1^3) , where t_2=4 sec ,t_1=2 sec=2 (4-2 )+ 1100(4^3-2^3)=4+ 1100 (56 )=4.56m ∴v_ av= xt_2-t_1= 4.564-2= 4.562=2.28m/s

$A car travels in a straight line along a road. Its distance x from a stop sign is given as a function of t by the equation x (t) = αt + β t^{3}, where α = 2.0 m / s, β = 0.01 m / s^{3} . Calculate the average velocity of the car in the time interval t = 2.00 s to 4.00 s .$

Solution

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