If the velocity of a particle moving along a straight line with uniform acceleration, is given by V= ( 196-16X ) ms^-1, then its acceleration is ( x is displacement of the particle)

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Correct answer: C. (c) Velocity of a particle is given by v= 196-16x ⇒v^2=196-16x2v dv dt=-16 dx dtv dv dt=-8v Acceleration, a=-8m/s^2

$If the velocity of a particle moving along a straight line with uniform acceleration, is given by V = (196 - 16 X) ms^{- 1}, then its acceleration is (x is displacement of the particle)$

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