A ball is projected from the ground with a speed 15 ms^-1 at an angle θ with horizontal so that its range and maximum height are equal, then 'tanθ' will be equal to

Question

Accepted Answer

Correct answer: D. (d) R = H 2 v_x×v_yg= v_y^22 g v_x= v_y4;u c o s θ= u s i n θ4 t a n θ=4

$A ball is projected from the ground with a speed 15 m s^{- 1} at an angle θ with horizontal so that its range and maximum height are equal, then 'tan θ' will be equal to$

Solution

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