The motion of a particle along a straight line is described by equation:
x = 8 + 12 t – $t^{3}$ where x is in meter and t in second. The retardation of the particle when its velocity becomes zero, is:

Question

The motion of a particle along a straight line is described by equation: x = 8 + 12 t – t^3 where x is in meter and t in second. The retardation of the particle when its velocity becomes zero, is:

Accepted Answer

Correct answer: D. (d) X = 8 +12t – t^3 V = 0+12 –3t2 = 0 3t2 = 12 t = 2sec a= dv dt = 0 – 6t a [t = 2] = –12 m/s2 retardation = 12 m/s2

$The motion of a particle along a straight line is described by equation: x = 8 + 12 t - t^{3} where x is in meter and t in second. The retardation of the particle when its velocity becomes zero, is:$

Solution

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