A car starts from rest and accelerates at $5 m / s^{2}$ . At $t = 4 s$ , a ball is dropped out of a
window by a person sitting in the car. What is the velocity and acceleration of the ball at $t = 6 s$ ? (Take, $g = 10 m / s^{2}$ ) [NEET 2021]

Question

A car starts from rest and accelerates at

5 m / s^{2}

. At

t = 4 s

, a ball is dropped out of a
window by a person sitting in the car. What is the velocity and acceleration of the ball at

t = 6 s

? (Take,

g = 10 m / s^{2}

) [NEET 2021]

Accepted Answer

Correct answer: A. (a) Given, Initial velocity, u=0 m/s Acceleration, a=5 m/s^2 Velocity at t=4 s ,v=u+ at v=5 4=20 m/s At this time a ball is dropped out of a window by a person sitting in the car. The velocity of ball after t=6 s is given by Vertical velocity of v_y=u_ ball+a ( t )=0+10 (6-4 )=20 ms^-1 Horizontal velocity of ball, v_x=20 ms^-1 So, magnitude of velocity of ball v_ net= v_x^2+v_y^2=20 2 m/s Acceleration of the ball will be equal to gravitational acceleration g. i.e. 10 m/s^2

$A car starts from rest and accelerates at 5 m / s^{2} . At t = 4 s, a ball is dropped out of a window by a person sitting in the car. What is the velocity and acceleration of the ball at t = 6 s ? (Take, g = 10 m / s^{2}) [NEET 2021]$

Solution

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